4 solutions

  • 0
    @ 2026-7-14 9:21:08

    #include<bits/stdc++.h> using namespace std; int main(){

    double x;
    cin>>x;
    if      (x<=10) printf("%.2lf",x*0.8+0.2);
    else if (x<=20) printf("%.2lf",8+(x-10)*0.75+0.2);
    else if (x<=30) printf("%.2lf",15.5+(x-20)*0.7+0.2);
    else cout <<"Fail";
    
    return 0;
    

    }

    Information

    ID
    2832
    Time
    1000ms
    Memory
    64MiB
    Difficulty
    1
    Tags
    # Submissions
    228
    Accepted
    45
    Uploaded By