1 solutions
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1
#include<bits/stdc++.h> using namespace std; int a[111110],b[111110],c[111110]; int main() { int n,m,cnt=0;cin>>n>>m; for(int i=1;i<=m;i++) { cin>>b[i]>>c[i]; a[b[i]]=c[i]; } for(int i=1;i<=m;i++) { a[b[i]]=min(a[b[i]],c[i]); } for(int i=1;i<=n;i++) { cnt+=a[i]; } cout<<cnt; return 0; }
Information
- ID
- 3020
- Time
- 1000ms
- Memory
- 256MiB
- Difficulty
- 10
- Tags
- # Submissions
- 3
- Accepted
- 1
- Uploaded By