11 solutions

  • 1
    @ 2026-10-18 11:34:34
    
    #include<bits/stdc++.h>
    using namespace std;
    double a[110][110];
    int main(){
    
    	int n;
        double s=0,sum=0;
        cin>>n;
        int y=1,x=n;
        for(int i=1;i<=n;i++){
            for(int j=1;j<=n;j++){
                cin>>a[i][j];
            }
        }
        for(int i=1;i<=n;i++){
            for(int j=1;j<=n;j++){
                if(abs(i-y)+abs(j-x)<n-1){
                    sum+=a[i][j];
                    s++;
                }
            }
        }
        printf("%.1lf",sum/s);
        
    	return 0;
    }
    

    Information

    ID
    70
    Time
    1000ms
    Memory
    256MiB
    Difficulty
    1
    Tags
    (None)
    # Submissions
    209
    Accepted
    64
    Uploaded By