11 solutions
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1
#include<bits/stdc++.h> using namespace std; double a[110][110]; int main(){ int n; double s=0,sum=0; cin>>n; int y=1,x=n; for(int i=1;i<=n;i++){ for(int j=1;j<=n;j++){ cin>>a[i][j]; } } for(int i=1;i<=n;i++){ for(int j=1;j<=n;j++){ if(abs(i-y)+abs(j-x)<n-1){ sum+=a[i][j]; s++; } } } printf("%.1lf",sum/s); return 0; }
Information
- ID
- 70
- Time
- 1000ms
- Memory
- 256MiB
- Difficulty
- 1
- Tags
- (None)
- # Submissions
- 209
- Accepted
- 64
- Uploaded By