7 solutions
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1
#include<bits/stdc++.h> using namespace std; int a[110][110],b[110][110]; int main() { int m,n,s=0; cin>>m>>n; for(int i=1;i<=m;i++){ for(int j=1;j<=n;j++){ int c; cin>>c; a[i][j]=c; } } for(int i=1;i<=m;i++){ for(int j=1;j<=n;j++){ int d; cin>>d; b[i][j]=d; } } //for(int i=1;i<=m;i++){ // for(int j = 1;j<=n;j++){ // cout<<a[i][j]<<" "; // }cout<<endl; //} //for(int i=1;i<=m;i++){ // for(int j = 1;j<=n;j++){ // cout<<b[i][j]<<" "; // }cout<<endl; //} for(int i=1;i<=m;i++){ for(int j=1;j<=n;j++){ if(a[i][j]==b[i][j]) s++; } } //cout<<s<<' '<<m*n<<endl; double A=s*1.0/(n*m)*100; cout<<fixed<<setprecision(2)<<A; return 0; }
Information
- ID
- 905
- Time
- 1000ms
- Memory
- 256MiB
- Difficulty
- 1
- Tags
- (None)
- # Submissions
- 128
- Accepted
- 51
- Uploaded By