3 solutions
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1
#include<bits/stdc++.h> using namespace std; int a[110][110],b[110][110]; int main(){ int n,m; cin>>n>>m; for(int i=1;i<=n;i++){ for(int j=1;j<=m;j++){ cin>>a[i][j]; } } for(int i=1;i<=n;i++){ for(int j=1;j<=m;j++){ //把除了周围四条边以外的数为该数及其上下左右相邻四个像数的平均(舍入到最接近的整数) if(i==n||i==1||j==m||j==1){ cout<<a[i][j]<<" "; }else{ b[i][j]=round((a[i][j]+a[i-1][j]+a[i+1][j]+a[i][j-1]+a[i][j+1])/5.0); cout<<b[i][j]<<' '; } } cout<<'\n'; } return 0; }
Information
- ID
- 906
- Time
- 1000ms
- Memory
- 256MiB
- Difficulty
- 1
- Tags
- (None)
- # Submissions
- 123
- Accepted
- 42
- Uploaded By