4 solutions

  • -4
    @ 2025-5-17 14:14:40
    #iostream<inclued>
    using namespace std;
    const int N=110;
    int a[N];
    int main()
    {
    	int n;
    	string si;
    	cin>>s;
    	bool s=0;
    	for(int i=0;i<n;i++)
    	{
    		cin>>a[i];
    		si+=a[i];
    	}
    	int res=1;
    	int ave=s/si;
    	if(ave*n==s) res=1;
    	else
    	{
    		for(int i=len(si);i>=n;n--)
    		{
    			if(n==a[i])
    			{
    				a[i+1]=a[i+1]-(ave-a[i]);
    			}
    		}
    	}
    	cout<<res;
     	return 0;
    }
    
    

Information

ID
1012
Time
1000ms
Memory
256MiB
Difficulty
3
Tags
(None)
# Submissions
73
Accepted
27
Uploaded By