2 solutions

  • -1
    @ 2025-8-11 15:38:23
    #include<bits/stdc++.h>
    using namespace std;
    int main()
    {
    	int n,m;
    	cin>>n>>m;
    	char a=(m/n)+'A'-1;
    	if(m%n!=0) a++;
    	cout<<a;
    	return 0;
    }
    

    【例】[ABC257A] A 到 Z 字符串 2(A to Z String 2)

    Information

    ID
    2404
    Time
    1000ms
    Memory
    256MiB
    Difficulty
    1
    Tags
    (None)
    # Submissions
    130
    Accepted
    44
    Uploaded By