6 solutions

  • 5
    @ 2025-4-26 15:11:59
    #include<bits/stdc++.h>
    using namespace std;
    int main()
    {
    	int a,b;
    	cin>>a>>b;
    	int t=b/a; //计算应该是第几个字母
    	if(b%a==0) t--; //如果是整倍数,商需要减一
    	char c='A'+t;
    	cout<<c; 
    	return 0;
    }
    
    • 3
      @ 2025-12-27 10:28:36

      #include<bits/stdc++.h> using namespace std; int main() { int a,b; cin>>a>>b; int t=b/a;
      if(b%a==0)
      { t--; } char c='A'+t;
      cout<<c; return 0; }

      • 1
        @ 2026-5-16 9:31:53

        #include<bits/stdc++.h> using namespace std; int main() {

        int a,b;
        
        cin>>a>>b;
        
        int t=b/a;
        
        if(b%a==0)
        {
        	t--;
        }
        char c='A'+t;
        
        cout<<c; 
        
        return 0;
        

        }

        • 0
          @ 2026-5-16 9:36:06

          #include<bits/stdc++.h>

          using namespace std;

          int main()

          {

          int a,b;
          
          cin>>a>>b;
          
          int t=b/a;
          
          if(b%a==0)
          
          {
          	t--;
          
          }
          char c='A'+t;
          
          cout<<c; 
          
          return 0;
          

          }

          • 0
            @ 2026-5-16 9:35:19

            #include<bits/stdc++.h>

            using namespace std;

            int main() { int a,b;

            cin>>a>>b;
            
            int t=b/a;
            
            if(b%a==0)
            
            {
            	t--;
            }
            char c='A'+t;
            
            cout<<c; 
            
            return 0;
            

            }

            • -1
              @ 2025-8-11 15:38:23
              #include<bits/stdc++.h>
              using namespace std;
              int main()
              {
              	int n,m;
              	cin>>n>>m;
              	char a=(m/n)+'A'-1;
              	if(m%n!=0) a++;
              	cout<<a;
              	return 0;
              }
              
              • 1

              Information

              ID
              2404
              Time
              1000ms
              Memory
              256MiB
              Difficulty
              1
              Tags
              (None)
              # Submissions
              223
              Accepted
              74
              Uploaded By