3 solutions

  • 3
    @ 2025-4-26 15:11:59
    #include<bits/stdc++.h>
    using namespace std;
    int main()
    {
    	int a,b;
    	cin>>a>>b;
    	int t=b/a; //计算应该是第几个字母
    	if(b%a==0) t--; //如果是整倍数,商需要减一
    	char c='A'+t;
    	cout<<c; 
    	return 0;
    }
    
    • 1
      @ 2025-12-27 10:28:36

      #include<bits/stdc++.h> using namespace std; int main() { int a,b; cin>>a>>b; int t=b/a;
      if(b%a==0)
      { t--; } char c='A'+t;
      cout<<c; return 0; }

      • -1
        @ 2025-8-11 15:38:23
        #include<bits/stdc++.h>
        using namespace std;
        int main()
        {
        	int n,m;
        	cin>>n>>m;
        	char a=(m/n)+'A'-1;
        	if(m%n!=0) a++;
        	cout<<a;
        	return 0;
        }
        
        • 1

        Information

        ID
        2404
        Time
        1000ms
        Memory
        256MiB
        Difficulty
        1
        Tags
        (None)
        # Submissions
        181
        Accepted
        61
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