1 solutions

  • 2
    @ 2026-4-26 11:18:43
    #include<bits/stdc++.h>
    using namespace std;
    typedef long long LL;
    const int N=3e5+10;
    int p[N];
    int main()
    {
    	int n;
    	cin>>n;
    	for(int i=1;i<=n;i++)
    	{
    		cin>>p[i];
    	}
    	priority_queue<int,vector<int>,greater<int>> q; //小根堆 
    	LL ans=0;
    	for(int i=1;i<=n;i++)
    	{
    		if(q.size()&&q.top()<p[i]) //有可买卖的股票 
    		{
    			ans-=q.top(); //以前那个不卖 
    			q.pop(); //删除以前的 
    			ans+=p[i]; //现在卖		
    			q.push(p[i]);  //为了方便以后反悔 
    		}
    		q.push(p[i]); //买当前这个 
    	}
    	cout<<ans;
    	return 0; 
    }
    
    • 1

    Information

    ID
    3056
    Time
    1000ms
    Memory
    256MiB
    Difficulty
    3
    Tags
    (None)
    # Submissions
    2
    Accepted
    2
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