1 solutions

  • 1
    @ 2026-6-17 18:51:12
    #include<bits/stdc++.h>
    using namespace std;
    int main()
    {
        int a; 
    	char c;
        cin>>a>>c;
        int s=8; //基础费用 
      	int w=a-1000;
      	if(w>0) //超重的部分 
      	{
      		s=s+(w+500-1)/500*4;
    	}
    	if(c=='y') //加急 
    	{
    		s=s+5;
    	}
    	cout<<s;
        return 0;
    }
    
    
    • 1

    Information

    ID
    857
    Time
    1000ms
    Memory
    256MiB
    Difficulty
    3
    Tags
    (None)
    # Submissions
    553
    Accepted
    121
    Uploaded By