3 solutions

  • 0
    @ 2026-6-21 14:39:20
    #include<bits/stdc++.h>
    using namespace std;
    int main()
    {
    	double a,b;
    	cin>>a>>b;
    	int c=a*b/10;
    	int d=c%10;
    	int e=(c%100-d)/10;
    	if(d<=4)
    	{
    		cout<<c-d;
    	}
    	else
    	{
    		cout<<c-d+10;
    	}
    	return 0; 
    }
    
    • 0
      @ 2025-12-13 16:15:46
      #include<bits/stdc++.h>
      using namespace std;
      int main()
      {
          double n,m;cin>>n>>m;
          int y=n/10*m;
          int g=y%10;
          if(g>=5)
          {
              y=y+10-g;
          }
          else y-=g;
          cout<<y;
          return 0;
      }
      
      • -1
        @ 2025-7-30 15:04:04
        #include<bits/stdc++.h>
        using namespace std;
        int main()
        {
            double n,m;cin>>n>>m;
            int y=n/10*m;
            int g=y%10;
            if(g>=5)
            {
                y=y+10-g;
            }
            else y-=g;
            cout<<y;
            return 0;
        }
        
        • 1

        Information

        ID
        2819
        Time
        1000ms
        Memory
        64MiB
        Difficulty
        1
        Tags
        # Submissions
        171
        Accepted
        58
        Uploaded By