8 solutions

  • 1
    @ 2026-6-13 18:51:23

    #include<bits/stdc++.h> using namespace std; int main() { int n;//表示有n个整数 double cnt;//设一个变量cnt,表示n个整数 cin>>n;//输出 for(int i=1;i<=n;i++) { int x; cin>>x;//第i个数 cnt+=x;//将第i个数加到总和里面 } cout<<cnt<<" ";//输出总和并空格 cout<<fixed<<setprecision(5)<<cnt/n;//总和除以数量求平均值(小数点保留5位) return 0; }

    • 1
      @ 2024-11-11 19:05:26
      #include<bits/stdc++.h>
      using namespace std;
      int main()
      {
          int n;
          double j = 0;
          cin>>n;
          for(int i = 1;i <= n;i++)
          {
              int x;
              cin>>x;
              j += x;
          }
          cout<<j<<" ";
          cout<<fixed<<setprecision(5)<<j / n;
          return 0;
      }
      
      
      • 0
        @ 2025-8-22 16:24:21
        #include<bits/stdc++.h>
        using namespace std;
        int n;
        int main(){
        	cin>>n;
        	double cnt=0;
        	double t;
        	for(int i=1;i<=n;i++){
        		cin>>t;
        		cnt+=t;
        	}
        	cout<<cnt<<' '<<fixed<<setprecision(5)<<cnt/n;
        	return 0;
        }
        
        • -3
          @ 2024-9-22 10:13:19
          #include<bits/stdc++.h>
          using namespace std;
          int main()
          {
          	double a=0,b=0,c=0,n=0,x=0;
          	int m=0;
          	cin>>n;
          	for(int i=1;i<=n;i++)
          	{
          		cin>>x;
          		m=m+x;
          	}
          	b=m/n;
          	cout<<m<<" ";
          	cout<<fixed<<setprecision(5)<<b;
          	
          	
          	return 0;
          }
          
          • -4
            @ 2025-8-5 14:10:48

            #include<bits/stdc++.h> using namespace std; int n; int main(){ cin>>n; double cnt=0; double t; for(int i=1;i<=n;i++){ cin>>t; cnt+=t; } cout<<cnt<<' '<<fixed<<setprecision(5)<<cnt/n; return 0; }

            • -4
              @ 2024-9-22 10:12:54
              #include<bits/stdc++.h>
              using namespace std;
              int main()
              {
              	int n;
              	cin>>n;
              	double cut;
              	for(int i=1;i<=n;i++)
              	{
              		int x;
              		cin>>x;
              		cut+=x;
              	}
              	cout<<cut<<" "<<fixed<<setprecision(5)<<cut/n;
                  return 0;
              }
              • -4
                @ 2024-9-8 15:05:40

                这题太难看

                • -9
                  @ 2024-9-22 10:13:17

                  #include<bits/stdc++.h> using namespace std; int main() { int a; cin>>a; int s; double d=0; for (int i=1;i<=a;i++) { cin>>s; d+=s; } cout<<d<<" "; cout<<fixed<<setprecision(5)<<d/a; return 0; }

                  • 1

                  Information

                  ID
                  872
                  Time
                  1000ms
                  Memory
                  256MiB
                  Difficulty
                  1
                  Tags
                  (None)
                  # Submissions
                  310
                  Accepted
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