3 solutions
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1
#include<bits/stdc++.h> using namespace std; int main() { int a; cin>>a; int c=0; int d=0; int e=0; int f=0; for (int i=1;i<=a;i++) { int b; cin>>b; if (b>=0 and b<=18) { c++; } else if (b>=19 and b<=35) { d++; } else if (b>=36 and b<=60) { e++; } else if (b>=61) { f++; } } cout<<fixed<<setprecision(2)<<c*100.0/a<<"%"<<endl; cout<<fixed<<setprecision(2)<<d*100.0/a<<"%"<<endl; cout<<fixed<<setprecision(2)<<e*100.0/a<<"%"<<endl; cout<<fixed<<setprecision(2)<<f*100.0/a<<"%"<<endl; return 0; } -
0
#include<bits/stdc++.h> using namespace std; int main() { int a; cin>>a; int c=0; int d=0; int e=0; int f=0; for(int i=1;i<=a;i++) { int b; cin>>b; if(b>0 and b<18) { c++;
} else if(b>19 and b<35) { d++; } else if(b>36 and b<60) { e++; } else if(b>=61) { f++; } } printf("%.2lf%%\n",c*100.0/a); printf("%.2lf%%\n",d*100.0/a); printf("%.2lf%%\n",e*100.0/a); printf("%.2lf%%\n",f*100.0/a); return 0;}
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0
#include<bits/stdc++.h> using namespace std; int main() { int a; cin>>a; int c=0; int d=0; int e=0; int f=0; for(int i=1;i<=a;i++) { int b; cin>>b; if(b>0 and b<18) { c++;
} else if(b>19 and b<35) { d++; } else if(b>36 and b<60) { e++; } else if(b>=61) { f++; } } printf("%.2lf%%\n",c*100.0/a); printf("%.2lf%%\n",d*100.0/a); printf("%.2lf%%\n",e*100.0/a); printf("%.2lf%%\n",f*100.0/a); return 0;}
- 1
Information
- ID
- 3478
- Time
- 1000ms
- Memory
- 256MiB
- Difficulty
- 1
- Tags
- # Submissions
- 40
- Accepted
- 26
- Uploaded By