1 solutions

  • 10
    @ 2024-5-15 13:58:30
    #include<bits/stdc++.h>
    using namespace std;
    int main()
    {
    	int a;
    	cin>>a;
    	int s=0; //约数的个数
    	for(int i=1;i<=a;i++)
    	{
    		if(a%i==0) //小的约数存在
    		{
    			s++;
    		}
    	}
    	cout<<s;
    	return 0;
    }
    
    
    • 1

    Information

    ID
    33
    Time
    1000ms
    Memory
    256MiB
    Difficulty
    1
    Tags
    (None)
    # Submissions
    311
    Accepted
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