3 solutions

  • 1
    @ 2026-9-13 14:23:43
    #include<bits/stdc++.h>
    using namespace std;
        int n;
        int a[1005];
    int main(){
        cin>>n;
        for(int i=1;i<=n;i++)
        {
            int x;
            cin>>x;
            a[x]++;
        }
        int maxn  = 0;
        for(int i = 0;i<=1000;i++){
            if(a[i]>a[maxn])
            {
                maxn=i;
            }
        }
        cout<<maxn;
        return 0;
    }
    
    • 1
      @ 2026-9-13 14:10:36
      #include<bits/stdc++.h>
      using namespace std;
          int n;
          int a[1000005];
      int main(){
          cin>>n;
          int s=0;
          int w=0;
          for(int i=1;i<=n;i++)
          {
              cin>>a[i];
          }
          for(int i=1;i<=n;i++)
          {
              int x=0;
              int y=0;
              for(int j=i+1;j<=n;j++)
              {
                  if(a[j]==a[i])
                  {
                      x+=1;
                  }
              }
              if(x>s)
              {
                  s=x;
                  w=a[i];
              }
          }
          cout<<w;
          return 0;
      }
      
      • 1
        @ 2026-6-13 19:40:49
        #include<bits/stdc++.h>
        using namespace std;
        const int N=1010;
        int a[N];
        int main()
        {
        	int n;
        	cin>>n;
        	for(int i=1;i<=n;i++)
        	{
        		int x;
        		cin>>x;
        		a[x]++; //统计x出现的次数 
        	}
        	int res=0;
        	for(int i=0;i<=1000;i++) //从小到大去遍历 
        	{
        		if(a[i]>a[res])
        		{
        			res=i;
        		}
        	}
        	cout<<res;
        	return 0;
        }
        
        
        • 1

        Information

        ID
        2870
        Time
        1000ms
        Memory
        64MiB
        Difficulty
        1
        Tags
        # Submissions
        89
        Accepted
        26
        Uploaded By