2 solutions

  • 1
    @ 2026-10-18 15:15:19
    #include<bits/stdc++.h>
    using namespace std;
    int n,m,a[3003],minn=1000000;
    int main(){
        cin>>n>>m;
        for(int i=1;i<=n;i++) cin>>a[i];
        for(int i=1;i<=n-(m-1);i++){
            int sum=0;
            for(int j=i;j<=i+(m-1);j++){
                sum+=a[j];
            }
            minn=min(sum,minn);
        }
        cout<<minn;
    return 0;
    }
    
    • -1
      @ 2026-2-5 10:17:44

      #include<bits/stdc++.h> using namespace std; const int N=3e3+10; int a[N]; int main() { int n,k; cin>>n>>k; for(int i=1;i<=n;i++) { cin>>a[i]; } int ans=1000000000; for(int i=1;i+k-1<=n;i++) { int sun=0; for(int j=i;j<=i+k-1;j++) { sun=sun+a[j]; } ans=min(ans,sun); } cout<<ans; return 0; }

      • 1

      Information

      ID
      1534
      Time
      1000ms
      Memory
      256MiB
      Difficulty
      1
      Tags
      (None)
      # Submissions
      108
      Accepted
      30
      Uploaded By