4 solutions

  • 2
    @ 2024-11-5 19:50:24
    #include<bits/stdc++.h> 
    using namespace std; 
    char s[255]; 
    int main() 
    { 
    	int cnt=0; 
    	cin.getline(s,255); 
    	for(int i=0;i<strlen(s);i++)
    	{ 
    		if(s[i]<='9' and s[i]>='0')
    		{ 
    			cnt++; 
    		} 
    	}
    	cout<<cnt;
    	return 0; 
    }
    

    这是题解,懂?🤨 [🥬🐔]

  • 0
    @ 2026-6-6 14:08:08
    #include<bits/stdc++.h>
    using namespace std;
    const int N=265;
    char a[N];
    int main(){
        int cnt=0;
        cin.getline(a,255);
        for(int i=0;i<strlen(a);i++){
            if(a[i]>='0' && a[i]<='9') cnt++;
        }
        cout<<cnt;
        return 0;
    }
    
    • 0
      @ 2026-2-3 16:20:18
      #include<bits/stdc++.h>
      using namespace std;
      char a[313];
      int main()
      {
      	cin.getline(a,313);
      	int cnt=0;
      	for (int i=0;i<313;i++)
      	{
      		if(a[i]>='0' and a[i]<='9')
      		{
      			cnt+=1;
      		}
      	}
      	cout<<cnt;
      	return 0;
      }	
      
      • -9
        @ 2024-6-22 20:00:55

        #include<bits/stdc++.h> using namespace std; char a[255]; int main() { int d=0; cin.getline(a,255); for(int i=0;i<strlen(a);i++){ if(a[i]<='9' and a[i]>='0'){ d++; } }

        cout<<d; return 0; }

        • 1

        Information

        ID
        913
        Time
        1000ms
        Memory
        256MiB
        Difficulty
        1
        Tags
        (None)
        # Submissions
        169
        Accepted
        28
        Uploaded By