3 solutions

  • 1
    @ 2025-3-17 17:59:47
    #include<bits/stdc++.h>
    using namespace std;
    const int N=1e2+10;
    char c[N];
    int main()
    {
        cin.getline(c,N);
        int n=strlen(c);
        for(int i=0;i<=n;i++)
        {
            if(c[i]>='a'&&c[i]<='z')
            {
                c[i]=c[i]-'a'+'A';
            }
        }
        cout<<c;
        return 0;
    }
    
  • -1
    @ 2026-5-2 10:24:08

    #include<bits/stdc++.h> using namespace std; const int N=1e2+10; char c[N]; int main() { cin.getline(c,N); int n=strlen(c); for(int i=0;i<=n;i++) { if(c[i]>='a'&&c[i]<='z') { c[i]=c[i]-'a'+'A'; } } cout<<c; return 0; }

    • -6
      @ 2024-10-5 11:49:48

      这是题解

      • 1

      Information

      ID
      915
      Time
      1000ms
      Memory
      256MiB
      Difficulty
      1
      Tags
      (None)
      # Submissions
      117
      Accepted
      57
      Uploaded By