1 solutions
-
0
#include<bits/stdc++.h> using namespace std; int main() { string s,t; cin>>s>>t; for(int w=1;w<s.size();w++) //枚举区间长度 { for(int c=0;c<w;c++) //枚举起点 { string now; for(int i=c;i<s.size();i+=w) { now+=s[i]; //拼接字符串 } if(now==t) { cout<<"Yes"<<endl; return 0; } } } cout<<"No"<<endl; return 0; }
- 1
Information
- ID
- 2672
- Time
- 1000ms
- Memory
- 256MiB
- Difficulty
- 3
- Tags
- # Submissions
- 23
- Accepted
- 14
- Uploaded By