3 solutions

  • 1
    @ 2024-8-22 15:43:37
    #include<bits/stdc++.h>
    using namespace std;
    struct Person{
        int id;
        int sc;
    };
    const int N=5010;
    Person p[N];
    bool cmp(Person a,Person b)
    {
        if(a.sc>b.sc)     return 1; //1.成绩从大到小 
        if(a.sc==b.sc&&a.id<b.id) return 1; //2.成绩相同报名号从小到大 
        return 0; 
    }
    int main()
    {
        int n,m;
        cin>>n>>m;
        for(int i=1;i<=n;i++)
            cin>>p[i].id>>p[i].sc;
        sort(p+1,p+n+1,cmp);
        int k=m*1.5;
        int t=k;
        while(t<=n&&p[k].sc==p[t].sc) t++; //走到最后一个不相等的地方,或者越界 、
    	t--; 
        cout<<p[k].sc<<" "<<t<<endl;
        for(int i=1;i<=t;i++)
        {
            cout<<p[i].id<<" "<<p[i].sc<<endl;
        }
        return 0;
    }
    
    • 0
      @ 2026-10-7 14:36:01
      #include<bits/stdc++.h>
      using namespace std;
      struct Person{
          int id;
          int sc;
      };
      const int N=5010;
      Person p[N];
      bool cmp(Person a,Person b)
      {
          if(a.sc>b.sc)     return 1; //1.成绩从大到小 
          if(a.sc==b.sc&&a.id<b.id) return 1; //2.成绩相同报名号从小到大 
          return 0; 
      }
      int main()
      {
          int n,m;
          cin>>n>>m;
          for(int i=1;i<=n;i++)
              cin>>p[i].id>>p[i].sc;
          sort(p+1,p+n+1,cmp);
          int k=m*1.5;
          int t=k;
          while(t<=n&&p[k].sc==p[t].sc) t++; //走到最后一个不相等的地方,或者越界 、
      	t--; 
          cout<<p[k].sc<<" "<<t<<endl;
          for(int i=1;i<=t;i++)
          {
              cout<<p[i].id<<" "<<p[i].sc<<endl;
          }
          return 0;
      }
      
      • -1
        @ 2026-7-31 21:37:41
        #include<bits/stdc++.h>
        using namespace std;
        struct node{
        	int id,ex;
        }a[5005];
        bool s[5005];
        int n,m;
        int sum;
        bool cmp(node c,node d){
        	if(c.ex>d.ex){
        		return 1;
        	}
        	if(c.ex==d.ex&&c.id<d.id){
        		return 1;
        	}
        	return 0;
        }
        int main()
        {
        	cin>>n>>m;
        	for(int i=1;i<=n;i++){
        		cin>>a[i].id>>a[i].ex;
        	}
        	sort(a+1,a+n+1,cmp);
        	sum=floor(m*1.5);
        	int t=a[sum].ex;
        	cout<<t<<" ";
        	int cnt=0;
        	for(int i=1;i<=n;i++){
        		if(a[i].ex>=t){
        			cnt++;
        			s[i]=1;
        		}
        	}
        	cout<<cnt<<endl;
        	for(int i=1;i<=n;i++){
        		if(s[i]){
        			cout<<a[i].id<<" "<<a[i].ex<<endl;
        		}
        	}
        	return 0;
        }
        
        • 1

        Information

        ID
        946
        Time
        1000ms
        Memory
        256MiB
        Difficulty
        3
        Tags
        (None)
        # Submissions
        72
        Accepted
        26
        Uploaded By