2 solutions

  • 2
    @ 2024-8-22 15:43:37
    #include<bits/stdc++.h>
    using namespace std;
    struct Person{
        int id;
        int sc;
    };
    const int N=5010;
    Person p[N];
    bool cmp(Person a,Person b)
    {
        if(a.sc>b.sc)     return 1; //1.成绩从大到小 
        if(a.sc==b.sc&&a.id<b.id) return 1; //2.成绩相同报名号从小到大 
        return 0; 
    }
    int main()
    {
        int n,m;
        cin>>n>>m;
        for(int i=1;i<=n;i++)
            cin>>p[i].id>>p[i].sc;
        sort(p+1,p+n+1,cmp);
        int k=m*1.5;
        int t=k;
        while(t<=n&&p[k].sc==p[t].sc) t++; //走到最后一个不相等的地方,或者越界 、
    	t--; 
        cout<<p[k].sc<<" "<<t<<endl;
        for(int i=1;i<=t;i++)
        {
            cout<<p[i].id<<" "<<p[i].sc<<endl;
        }
        return 0;
    }
    
    • 0
      @ 2026-7-31 21:37:41
      #include<bits/stdc++.h>
      using namespace std;
      struct node{
      	int id,ex;
      }a[5005];
      bool s[5005];
      int n,m;
      int sum;
      bool cmp(node c,node d){
      	if(c.ex>d.ex){
      		return 1;
      	}
      	if(c.ex==d.ex&&c.id<d.id){
      		return 1;
      	}
      	return 0;
      }
      int main()
      {
      	cin>>n>>m;
      	for(int i=1;i<=n;i++){
      		cin>>a[i].id>>a[i].ex;
      	}
      	sort(a+1,a+n+1,cmp);
      	sum=floor(m*1.5);
      	int t=a[sum].ex;
      	cout<<t<<" ";
      	int cnt=0;
      	for(int i=1;i<=n;i++){
      		if(a[i].ex>=t){
      			cnt++;
      			s[i]=1;
      		}
      	}
      	cout<<cnt<<endl;
      	for(int i=1;i<=n;i++){
      		if(s[i]){
      			cout<<a[i].id<<" "<<a[i].ex<<endl;
      		}
      	}
      	return 0;
      }
      
      • 1

      Information

      ID
      946
      Time
      1000ms
      Memory
      256MiB
      Difficulty
      3
      Tags
      (None)
      # Submissions
      64
      Accepted
      23
      Uploaded By