3 solutions
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1
#include<bits/stdc++.h> using namespace std; const int N=110; int a[N][N]; int main() { int n,m; cin>>n>>m; for (int i=1;i<=n;i++) { for (int j=1;j<=m;j++) { cin>>a[i][j]; } } for (int j=1;j<=m;j++) { for (int i=n;i>=1;i--) { cout<<a[i][j]<<" "; } cout<<endl; } return 0; }
- 1
Information
- ID
- 910
- Time
- 1000ms
- Memory
- 256MiB
- Difficulty
- 1
- Tags
- (None)
- # Submissions
- 68
- Accepted
- 35
- Uploaded By