2 solutions
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2
#include<bits/stdc++.h> using namespace std; const int N=260; int a[N],b[N],c[N]; string s1,s2; int main() { cin>>s1>>s2; int lena=s1.size(); int lenb=s2.size(); int lenc=max(lena,lenb)+1; for(int i=0,j=s1.size()-1;j>=0;i++,j--) { a[i]=s1[j]-'0'; } for(int i=0,j=s2.size()-1;j>=0;i++,j--) { b[i]=s2[j]-'0'; } int t=0; for(int i=0;i<=lenc;i++) { t=t+a[i]+b[i]; c[i]=t%10; t/=10; } while(lenc>0&&c[lenc]==0) lenc--; for(int i=lenc;i>=0;i--) { cout<<c[i]; } return 0; }
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1
#include<bits/stdc++.h> using namespace std; const int N=210; int a[N],b[N],c[N]; int main() { string s1,s2; cin>>s1>>s2; reverse(s1.begin(),s1.end()); reverse(s2.begin(),s2.end()); for(int i=0;i<s1.size();i++) { a[i]=s1[i]-'0'; } for(int i=0;i<s2.size();i++) { b[i]=s2[i]-'0'; } int lenc=max(s1.size(),s2.size())+1; for(int i=0,t=0;i<lenc;i++) //t表示进位 { c[i]=a[i]+b[i]+t; t=c[i]/10; c[i]=c[i]%10; } while(lenc&&c[lenc]==0) lenc--; for(int i=lenc;i>=0;i--) { cout<<c[i]; } return 0; }
- 1
Information
- ID
- 956
- Time
- 1000ms
- Memory
- 256MiB
- Difficulty
- 3
- Tags
- (None)
- # Submissions
- 123
- Accepted
- 31
- Uploaded By