1 solutions

  • 0
    @ 2026-5-24 14:37:31
    #include<bits/stdc++.h>
    using namespace std;
    typedef long long LL;
    const int N=1e5+10;
    LL n,x;
    int ans=0;
    vector<LL> g[N];
    void dfs(LL u,LL s)
    {
    	if(u==n) //枚举完了所有组
    	{
    		if(s==x) ans++;
    		return ;
    	}
    	for(auto j:g[u])
    	{
    		if(s*j>x) continue;//越界
    		dfs(u+1,s*j);//去下一个位置(累乘)
    	}
    }
    int main()
    {
    	cin>>n>>x;
    	for(int i=0;i<n;i++)
    	{
    		int t;
    		cin>>t;
    		while(t--)
    		{
    			int x;
    			cin>>x;
    			g[i].push_back(x);
    		}
    	}
    	dfs(0,1); //搜索
    	cout<<ans;
    	return 0;
    }
    
    • 1

    Information

    ID
    2753
    Time
    1000ms
    Memory
    256MiB
    Difficulty
    3
    Tags
    # Submissions
    21
    Accepted
    6
    Uploaded By