3 solutions
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1
#include<bits/stdc++.h> using namespace std; const int N=2e5+10; vector<int> g[N]; vector<int> ans; void dfs(int u,int fa) { ans.push_back(u);//走到了当前城市 for(auto j:g[u]) { if(j==fa) continue;//往回走的 dfs(j,u);//继续往下 ans.push_back(u);//又回来了 } } int main() { int n; cin>>n; for(int i=1;i<n;i++) { int a,b; cin>>a>>b; g[a].push_back(b); g[b].push_back(a); } for(int i=1;i<=n;i++) { sort(g[i].begin(),g[i].end()); //按照字典序排序 } dfs(1,-1);//去遍历所有节点 for(auto x:ans) { cout<<x<<" "; } return 0; } -
0
#include<bits/stdc++.h> using namespace std; const int N=2e5+10; vector<int> g[N]; //g[i]里面储存的是i可以走到的所有点 void dfs(int u,int fa) { cout<<u<<" "; for(auto j:g[u]) { if(j==fa) continue; dfs(j,u); cout<<u<<" "; } } int main() { int n; cin>>n; for(int i=1;i<n;i++) { int a,b; cin>>a>>b; g[a].push_back(b); g[b].push_back(a); } for(int i=1;i<=n;i++) { sort(g[i].begin(),g[i].end()); } dfs(1,-1);//当前点和当前点的父节点 return 0; } -
0
#include<bits/stdc++.h> using namespace std; int n; vector<int>v[200010]; void dfs(int x,int fa) { cout<<x<<" "; for(auto y:v[x]) { if(y!=fa) { dfs(y,x); } } if(x!=1) { cout<<fa<<" "; } } signed main() { cin>>n; for(int i=1;i<n;i++) { int a,b; cin>>a>>b; v[a].push_back(b); v[b].push_back(a); } for(int i=1;i<=n;i++) { sort(v[i].begin(),v[i].end()); } dfs(1,0); return 0; }
- 1
Information
- ID
- 2772
- Time
- 1000ms
- Memory
- 256MiB
- Difficulty
- 3
- Tags
- # Submissions
- 14
- Accepted
- 9
- Uploaded By