2 solutions

  • 0
    @ 2025-9-21 11:13:41
    #include<bits/stdc++.h>
    using namespace std;
    int main()
    {
        int n;cin>>n;
        for(int i=1;i<=n;i++)
        {
            int x;cin>>x;
            int res=0;
            int t=x;
            while(t)
            {
                t/=10;
                res++;
            }
            t=x;
            int q=0;
            while(t)
            {
                q+=pow(t%10,res);
                t/=10;
            }
            if(q==x) cout<<"T"<<endl;
            else cout<<"F"<<endl;
        }
        return 0;
    }
    
    • 0
      @ 2025-8-28 13:48:50
      #include<bits/stdc++.h>
      using namespace std;
      int main()
      {
      	int t;
      	cin>>t;
      	while(t--)
      	{
      		int a;
      		cin>>a;
      		int a1=a;
      		int cnt=0;//当前a的位数
      		while(a1)
      		{
      			cnt++;
      			a1/=10;
      		}
      		int s=0; //当前每位的cnt次方的和
      		a1=a;
      		while(a1)
      		{
      			int ge=a1%10;
      			s=s+pow(ge,cnt);
      			a1/=10;
      		}
      		if(s==a)
      		{
      			cout<<"T"<<endl;	
      		}
      		else
      		{
      			cout<<"F"<<endl;
      		}
      	}
      	return 0;
      }
      
      • 1

      Information

      ID
      1176
      Time
      1000ms
      Memory
      256MiB
      Difficulty
      3
      Tags
      (None)
      # Submissions
      71
      Accepted
      15
      Uploaded By