自己掰开

#include <iostream>
using namespace std;

int main() {
    int n;
    cin >> n;
    
    long long product = 1;  // 使用long long防止溢出
    const long long LIMIT = 1000000;
    
    for (int i = 0; i < n; i++) {
        int a;
        cin >> a;
        
        // 如果当前乘积已经超过或等于LIMIT，保持不变即可
        if (product <= LIMIT) {
            product *= a;
        }
    }
    
    if (product > LIMIT) {
        cout << ">1000000" << endl;
    } else {
        cout << product << endl;
    }
    
    return 0;
}