1 solutions

  • 2
    @ 2025-11-15 16:14:28
    #include<bits/stdc++.h>
    using namespace std;
    const int N=1e5+10;
    typedef pair<int,int> PII;
    vector<PII> g[N];
    #define x first
    #define y second 
    typedef long long LL;
    LL ans=0;
    void dfs(int u,int fa,LL sum)
    {
    	ans=max(ans,sum); //找到走到根节点的最长路径(只走一遍) 
    	for(auto t:g[u])
    	{
    		if(t.x==fa) continue;
    		dfs(t.x,u,sum+t.y);
    	}
    }
    int main()
    {
    	int n;
    	cin>>n;
    	LL s=0;
    	for(int i=1;i<n;i++)
    	{
    		int a,b,c;
    		cin>>a>>b>>c;
    		g[a].push_back({b,c});
    		g[b].push_back({a,c});
    		s+=c; //累加所有路径 
    	}
    	dfs(1,-1,0);
    	cout<<2*s-ans;
    	return 0;
    } 
    
    • 1

    Information

    ID
    2895
    Time
    1000ms
    Memory
    256MiB
    Difficulty
    10
    Tags
    # Submissions
    2
    Accepted
    2
    Uploaded By