1 solutions

  • 0
    @ 2025-11-8 14:55:28
    #include<bits/stdc++.h>
    using namespace std;
    int main()
    {
    	int n;
    	cin>>n;
    	string s;
    	cin>>s;
    	reverse(s.begin(),s.end());//翻转字符串
    	int sum=0;
    	for(int i=0;i<n;i++)
    	{
    		sum=sum+pow(2,i)*(s[i]-'0'); //权重乘以对应的数值 
    	} 
    	cout<<sum;
    	return 0;
    }
    
    • 1

    Information

    ID
    2857
    Time
    1000ms
    Memory
    64MiB
    Difficulty
    1
    Tags
    # Submissions
    12
    Accepted
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