1 solutions
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1
#include<bits/stdc++.h> using namespace std; const int N=20; int a[N][N]; int main() { int n; cin>>n; int cnt=1,x=n,y=1; for(int i=1;i<=n;i++) { x=n-i+1; y=0; if(i==1) { a[n][1]=cnt; cnt++; continue; } else { for(int j=1;j<=i;j++) { y++; a[x][y]=cnt; cnt++; } for(int j=1;j<=i-1;j++) { x++; a[x][y]=cnt; cnt++; } } } for(int i=1;i<=n;i++) { for(int j=1;j<=n;j++) { cout<<setw(4)<<a[i][j]; } cout<<endl; } return 0; }
- 1
Information
- ID
- 2874
- Time
- 1000ms
- Memory
- 64MiB
- Difficulty
- 10
- Tags
- # Submissions
- 3
- Accepted
- 2
- Uploaded By